# (Solved) : Read Code Odd Assume Numberlist Contains Entries 0 1 2 3 4 Duplicates Allowed Answer Quest Q42787159 . . .

Read over the code for has odd. Assume that number_list contains entries from {0, 1,2,3,4}, with duplicates allowed. Answer the questions below, assuming that n = len(number list) i def has_odd(number_list) -> bool: for i in range (len (number_list)): if number_list[i] % 2 == 1: return True return false (a) [3 marks] Find a good upper bound, U(n), for W Chas_odd(n). Prove that your upper bound is correct. (b) [3 marks] Find a lower bound, L(n), for W Chas_odd(n) that is in the same asymptotic complexity class as U(n) (that’s what I mean by “good” in the previous part). Prove that your lower bound is correct, then state and justify a simple big-Theta complexity class for W Chas.odd(n) (c) [3 marks) If has odd returns True after examining k entries in number_list, count this as k steps. If an has_odd examines all n entries in number_list and proceeds to return False count this as n + 1 steps. Using these assumptions, show how to calculate the average number of steps for all inputs to has odd of length 2. (d) [3 marks] Use the step-counting assumptions in the previous part to devise a formula for the average number of steps for all inputs to has_odd of length n. You may find it useful to recall (where r is some positive real number) non rpnt1 i=n- 1 = -1+ (n − 1)2 Show your work. Show transcribed image text Read over the code for has odd. Assume that number_list contains entries from {0, 1,2,3,4}, with duplicates allowed. Answer the questions below, assuming that n = len(number list) i def has_odd(number_list) -> bool: for i in range (len (number_list)): if number_list[i] % 2 == 1: return True return false (a) [3 marks] Find a good upper bound, U(n), for W Chas_odd(n). Prove that your upper bound is correct. (b) [3 marks] Find a lower bound, L(n), for W Chas_odd(n) that is in the same asymptotic complexity class as U(n) (that’s what I mean by “good” in the previous part). Prove that your lower bound is correct, then state and justify a simple big-Theta complexity class for W Chas.odd(n) (c) [3 marks) If has odd returns True after examining k entries in number_list, count this as k steps. If an has_odd examines all n entries in number_list and proceeds to return False count this as n + 1 steps. Using these assumptions, show how to calculate the average number of steps for all inputs to has odd of length 2. (d) [3 marks] Use the step-counting assumptions in the previous part to devise a formula for the average number of steps for all inputs to has_odd of length n. You may find it useful to recall (where r is some positive real number) non rpnt1 i=n- 1 = -1+ (n − 1)2 Show your work.

Answer to Read over the code for has odd. Assume that number_list contains entries from {0, 1,2,3,4}, with duplicates allowed. Ans…

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