Root Finding 3. Given the function f(x) = x2 + 6x + 8 and a tolerance of tol = 0.1, use the Bisection method to find a root of this function. Assume the initial range is Xi = -3 and XR = 0. Provide your calculations in the following table. (2) f(x) -1.00 XR f(xp) 8.00 XNew f(xnew) Initial Range -3.00 0.00 XNew Updated Range XNew Updated Range XNew Updated Range XNew Updated Range XNew Updated Range XNew Updated Range XNew | Updated Range XNew Updated Range XNew Updated Range XNew Show transcribed image text Root Finding 3. Given the function f(x) = x2 + 6x + 8 and a tolerance of tol = 0.1, use the Bisection method to find a root of this function. Assume the initial range is Xi = -3 and XR = 0. Provide your calculations in the following table. (2) f(x) -1.00 XR f(xp) 8.00 XNew f(xnew) Initial Range -3.00 0.00 XNew Updated Range XNew Updated Range XNew Updated Range XNew Updated Range XNew Updated Range XNew Updated Range XNew | Updated Range XNew Updated Range XNew Updated Range XNew
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Answer to Root Finding 3. Given the function f(x) = x2 + 6x + 8 and a tolerance of tol = 0.1, use the Bisection method to find a r…