python question
The user-defined function below calculates arctanh(u) for a single value u. [30]: from math import tanh, cosh # calculate inverse hyperbolic tangent to le-6 accuracy def arctanh(u): x = 0.0 delta = 1.0 eps = 1e-6 while abs(delta) > eps: delta = (tanh(x) – u)*cosh(x)**2 x -= delta return(x) Exercise Given the code above, calculate arctanh(u) for u on the interval 1-1, 1[ and plot the result, using a reasonable number of points. [ ]: Show transcribed image text The user-defined function below calculates arctanh(u) for a single value u. [30]: from math import tanh, cosh # calculate inverse hyperbolic tangent to le-6 accuracy def arctanh(u): x = 0.0 delta = 1.0 eps = 1e-6 while abs(delta) > eps: delta = (tanh(x) – u)*cosh(x)**2 x -= delta return(x) Exercise Given the code above, calculate arctanh(u) for u on the interval 1-1, 1[ and plot the result, using a reasonable number of points. [ ]:
Expert Answer
Answer to The user-defined function below calculates arctanh(u) for a single value u. [30]: from math import tanh, cosh # calculat…